- #1

rab99

- 104

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Referring to fig 1

I have a particle accelerator in a space ship. The accelerator part is a point A and the particles are accelerated to point B. The velocity of the particles is measured by the observer at D and the energy input is measured by a meter at E.

All of the points and the observer are at rest wrt the space ship

V is the velocity of the spaceship which of course will be unknown to the observer.

I want to try an experiment to see if the observer can tell if he is moving.

While the spaceship is stationary on the launch pad the observer accelerates a particle up 0.99c as measured by the observer and measures the energy required. Let's say the energy to do this is X

While the spaceship is still stationary on the launch pad the observer turns the accelerator through 180 degrees so point B is now where point A used to be and point A is where point B used to be. The observer again accelerates a particle up 0.99c as measured by the observer and measures the energy required. Let's say the energy to do this is Y

Will Y be equal to X I think it would be does anyone disagree?

Finally the rocket takes off and accelerate until it reaches it terminal velocity at which time it will achieve a constant velocity.

The observer now accelerates a particle up 0.99c as measured by the observer and measures the energy to required. Let's say the energy to do this is W.

The observer again turns the accelerator through 180 degrees so point B is now where point A used to be and point A is where point B used to be. The observer again accelerates a particle up 0.99c as measured by the observer and measures the energy required. Let's say the energy to do this is Z.

Assume the spaceship is traveling at a velocity of 0.5c

Is

X = Y

Z = X

W = X

will all the energy measurements be the same. If they are not then the observer will think two things

1 something is broken

2 I must be moving and the velocity on me moving is adding or subtracting from the velocity of the particle thus requiring less or more energy to accelerate it.

I have a particle accelerator in a space ship. The accelerator part is a point A and the particles are accelerated to point B. The velocity of the particles is measured by the observer at D and the energy input is measured by a meter at E.

All of the points and the observer are at rest wrt the space ship

V is the velocity of the spaceship which of course will be unknown to the observer.

I want to try an experiment to see if the observer can tell if he is moving.

While the spaceship is stationary on the launch pad the observer accelerates a particle up 0.99c as measured by the observer and measures the energy required. Let's say the energy to do this is X

While the spaceship is still stationary on the launch pad the observer turns the accelerator through 180 degrees so point B is now where point A used to be and point A is where point B used to be. The observer again accelerates a particle up 0.99c as measured by the observer and measures the energy required. Let's say the energy to do this is Y

Will Y be equal to X I think it would be does anyone disagree?

Finally the rocket takes off and accelerate until it reaches it terminal velocity at which time it will achieve a constant velocity.

The observer now accelerates a particle up 0.99c as measured by the observer and measures the energy to required. Let's say the energy to do this is W.

The observer again turns the accelerator through 180 degrees so point B is now where point A used to be and point A is where point B used to be. The observer again accelerates a particle up 0.99c as measured by the observer and measures the energy required. Let's say the energy to do this is Z.

Assume the spaceship is traveling at a velocity of 0.5c

Is

X = Y

Z = X

W = X

will all the energy measurements be the same. If they are not then the observer will think two things

1 something is broken

2 I must be moving and the velocity on me moving is adding or subtracting from the velocity of the particle thus requiring less or more energy to accelerate it.