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Pauli Exclusion Principle

  1. Feb 18, 2012 #1
    According to Slater determinant, can one say that two bosons are able to place in the same position X , but two fermions can not, no matter what their states are?
     
  2. jcsd
  3. Feb 18, 2012 #2

    Bill_K

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    It's the total wavefunction that must be antisymmetric. This includes both the position and the spin (and any other degrees of freedom that may be present, like isospin). So for example a spin up fermion and a spin down fermion can have the same X.
     
  4. Feb 18, 2012 #3
    Thanks for replying, but According to Slater determinant when X1=X2 the antisymmetric wave function become zero.
     
  5. Feb 19, 2012 #4

    Bill_K

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    You're mistaken, hokhani. Since you don't believe me, take a look at the Slater Determinant page in Wikipedia. There it says, "The Slater determinant arises from the consideration of a wave function for a collection of electrons, each with a wave function known as the spin-orbital, χ(x), where x denotes the position and spin of the singular electron."

    Your reference may be doing the same thing: letting the notation x stand for both spin and position combined.
     
  6. Feb 19, 2012 #5
    Thanks very much
    As i found out, there are 3 factors determining the pauli exclusion principal:
    1) Particles' positions(x,y,z)
    2) Particles' spins
    3) Particles' energy states
    Would you tell me if i am wrong?
     
    Last edited: Feb 19, 2012
  7. Feb 19, 2012 #6
    If scientists have entangled more than two fermions, would that violate the principal?
     
  8. Feb 20, 2012 #7
    Excuse me; I was wrong
    In fact the third part covers the two other parts.
     
    Last edited: Feb 20, 2012
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