Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Pauli-lubanski pseudo-vecor

  1. Jul 15, 2008 #1

    I’m wondering if anybody could help me to prove the result of W2 (square of the pauli-lubanski pseudo-vecor).
  2. jcsd
  3. Jul 15, 2008 #2
    Re: Pauli-Lubanski

    See first equation on page 117 of http://www.arxiv.org/abs/physics/0504062

  4. Jul 15, 2008 #3
    Re: Pauli-Lubanski

    Thank you for your reply but in my case I need to start with


    And to end with


    Could any body tell me how to derive this
  5. Jul 15, 2008 #4


    User Avatar
    Science Advisor

    Re: Pauli-Lubanski

    use the identity

    \epsilon_{a}^{bcd}\epsilon^{a \bar{b} \bar{c} \bar{d}} = - \left| \begin{array}{ccc} \eta^{\bar{b}b} & \eta^{\bar{c}b} & \eta^{\bar{d}b} \\ \eta^{\bar{b}c} & \eta^{\bar{c}c} & \eta^{\bar{d}c} \\ \eta^{\bar{b}d} & \eta^{\bar{c}d} & \eta^{\bar{d}d} \end{array} \right|


    [tex]M_{ab} = - M_{ba}[/tex]


  6. Sep 8, 2008 #5
    Re: Pauli-Lubanski

    i tried to get an explicit form of this (Pauli-Lubanski pseudo vector) and i keep getting
    zero. i.e W=(0,0,0,0)...which would still make it an invariant; albeit a boring one.
    Looking at the form too, with M_ab=-M_ba it does seem that it should be zero.
    Can someone tell me what i might be doing wrong. Thanks
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook