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PCHEM Question

  1. Sep 12, 2009 #1
    A sample consisting of 1.00 mol of a van der Waals gas is compressed from 20.0 L to 10.0 L at 300 K. In the process, 20.2 kJ of work is done on the gas. Given that u = {(2a/RT)-b}/Cp,m with Cp,m = 38.4 J K-1mol-1, a = 3.60 L2 atm mol-2, and b = 0.44 L mol-1, calculate deltaH for the process.

    Equations: deltaH = nCpdT


    deltaU = w

    1. H = U + PV DeltaH = q

    2. dH = (partialH/partialT)sub(p)DT + (partialH/partialP)sub(T)DP

    3. Cp = q/dT = (partialH/partialT)sub(p)

    4. deltaH = CpdT

    5. so dH = deltaH + (partialH/partialP)sub(T)DP

    and then dH = deltaH - CpudP

    gotta figure out what deltaH is, but to do that i gotta find dH, but that just leads me back to equation 2. and then im just going round in circles. need help. thanks.

    3. The attempt at a solution
  2. jcsd
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