- #1
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Given this equation:
[tex]
u_t-u_{xx}=0
[/tex]
[tex]
u(x,0)=x(2-x)
x\in[0,2]
[/tex]
[tex]
u(0,t)=u(2,t)=0
t\in[0,2]
[/tex]
Verify that u(x,t)=u(2-x,t) is a solution.
To do this would I just show that:
u(0,t)=u(2,t)
u(2-x,0)=(2-x) but off by a scalar.
[tex]
u_t-u_{xx}=0
[/tex]
[tex]
u(x,0)=x(2-x)
x\in[0,2]
[/tex]
[tex]
u(0,t)=u(2,t)=0
t\in[0,2]
[/tex]
Verify that u(x,t)=u(2-x,t) is a solution.
To do this would I just show that:
u(0,t)=u(2,t)
u(2-x,0)=(2-x) but off by a scalar.