# PDE with complex argument

I'm in truble with a partial differential equation. Actually it is a system of PDE but It would be useful to solve at least one of them.
The most easy one is this one

$$2 \bar{\xi}\left(\bar{s},\bar{t},\bar{u}\right) - 2 \xi\left(s,t,u\right) + \left(s-\bar{s}\right)\left(\bar{\partial}_\bar{s} \bar{\xi} + \partial_s \xi \right) = 0$$

This equation can be simplified to

$$2 A^*\left(z^*\right) - 2 A\left(z\right) + \left(z-z^*\right)\left(\bar{\partial}_{z^*}A^*+\partial_{z}A\right)= 0$$

I further developed my computation using $$A(z) = u(x,y) + i v(x,y)$$ with $$u,v \in \mathbb{R}$$
finding (I used Cauchy-Riemann equations)
$$v(x,y) = y^2 f(x+y)$$
Here is where I get stucked since I cannot find a suitable form of "f(x+y)" in order to obtain "u" and satisfy Cauchy-Riemann equations...
Any ideas?

I'm in truble with a partial differential equation. Actually it is a system of PDE but It would be useful to solve at least one of them.
The most easy one is this one

$$2 \bar{\xi}\left(\bar{s},\bar{t},\bar{u}\right) - 2 \xi\left(s,t,u\right) + \left(s-\bar{s}\right)\left(\bar{\partial}_\bar{s} \bar{\xi} + \partial_s \xi \right) = 0$$

This equation can be simplified to

$$2 A^*\left(z^*\right) - 2 A\left(z\right) + \left(z-z^*\right)\left(\bar{\partial}_{z^*}A^*+\partial_{z}A\right)= 0$$

Any ideas?
Consider the expression:

$$\bar{\partial}_{z^*}A^*$$

I assume that means:

$$\overline{\frac{\partial \bar{f}}{\partial\bar{s}}}$$

but we know that:

$$\frac{\partial \overline{f}}{\partial \overline{s}}=\overline{\frac{\partial f}{\partial s}}$$

which means you have:

$$2\overline{A}(\overline{z})-2A(z)+2(z-\overline{z})\frac{\partial A}{\partial z}=0$$

I'm afraid I use the wrong notation or maybe I didn't understand at all! =)
with
$$\bar{\partial}_{\bar{s}} \xi^*$$
I mean the derivate of xi* wrt the complex conjugate of s (i.e. \bar{s}). I use the bar over the partial derivative to point out that the derivate is made over \bar{s} and not s. Sorry about this misleading notation! :)

I'm afraid I use the wrong notation or maybe I didn't understand at all! =)
with
$$\bar{\partial}_{\bar{s}} \xi^*$$
I mean the derivate of xi* wrt the complex conjugate of s (i.e. \bar{s}). I use the bar over the partial derivative to point out that the derivate is made over \bar{s} and not s. Sorry about this misleading notation! :)
Ok, that's confussing. Tell you what, how about we just do it my way:

$$2\overline{A}(\overline{z})-2A(z)+2(z-\overline{z})\frac{d A}{d z}=0$$

Can we even solve that one? The conjugate variables really hit me with a surprise though and I'm not use to working with DEs like that. I mean what do you do with something like that? Is it even well-posed? Suppose nobody could help us and we had to do something with it, a thesis or something? What do we do? Suppose we could first look at:

$$\frac{dy}{dz}+\overline{y}(\overline{z})=0$$

Can we even do that one? Does it even make sense? Looks like another whole-semester type problem to me.

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I have to admit I'm confused too...
My problem, I mean in its original formulation, require to find the holomorphic Killing vector of a given Kahler manifold. In order to do that I found I have to solve that equation (and many more to be honest...).
Now I wondering if by $$\bar{A}(\bar{z})$$
they actually mean $$\left(A(z)\right)^*$$
In that case I can set $$A = u(x,y)+iv(x,y) \qquad \bar{A} = u(x,y)-iv(x,y)$$
For which I found this solution
$$u(x,y) = \frac{1}{2} C_1 \left(x^2-y^2\right)+C_2 x + C_3 \qquad v(x,y) = C_1 xy + C_2 y$$
Which is a bit tempting since it satisfy also Cauchy Riemann equations..

Now I wondering if by $$\bar{A}(\bar{z})$$
they actually mean $$\left(A(z)\right)^*$$
I think that means the conjugate of A at the conjugate of z. So if:

$$A(z)=iz$$

$$A(\overline{z})=i\overline{z}$$

$$\overline{A(\overline{z})}=-iz$$

Not sure though ok?

Bulletin from the front. :)

As I supposed they intended just the conjugation of the entire function not of both function and variables... So I solved, thank you anyway!