1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

PE Farmer

  1. Oct 25, 2005 #1
    A farmer uses a pump to lift water from a river to a arable land who lies 5.0m higher than the river. The pump exhaust an electrical effect of 1.0kW but only 65% is used to do the lifting. ok A) I have resolved the lifting work is 0,65*60 = 39kJ

    But B) is harder,,,, how much water is pumped up during a minute ...?

    I have no idea how to solv this please help me
     
  2. jcsd
  3. Oct 25, 2005 #2

    Päällikkö

    User Avatar
    Homework Helper

    In A) you've apparently solved how much work is used to lifting the water a minute.
    During this minute, how much water is lifted?
    Is the anwer in kg or m3? Doesn't really matter, you know their relation.

    What is the energy required to lift a ball of mass m to height h?
     
  4. Oct 25, 2005 #3

    mrjeffy321

    User Avatar
    Science Advisor

    You know that 65% of the pumps power (1 kW) is used to lift water.
    This means that every second, 650 J of energy is used by the pump to list water, multiply by 60 to get energy per minute.
    You know how much energy it will take to lift m kilograms of water h distance up against gravity g (mgh), since in this problem h and g are givens/constants, so just solve for m.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: PE Farmer
  1. Capacitor PE (Replies: 11)

  2. KE and PE (Replies: 3)

  3. PE & PE Energy (Replies: 3)

Loading...