Calculating Speed of Dropped Tennis Ball: Explaining Conservation of Energy

In summary, the speed of a tennis ball hitting the ground when dropped from a height of 20m can be calculated using the formula v = √(2gh). This is based on the principles of conservation of energy, which states that energy cannot be created or destroyed, only transferred from one form to another. In this case, the potential energy of the ball at the top of its drop is converted into kinetic energy as it falls, assuming there is no loss of energy due to external forces such as air resistance. This assumption is more reasonable on the moon, where there is less air resistance, compared to Earth.
  • #1
RachelT
9
0

Homework Statement


Using the formulae for potential energy and kinetic energy, find the speed that a tennis ball hits the ground when dropped from a height of 20m.

With reference to the principle of conservation of energy, explain why you could use these equations and what assumptions you have made.

Homework Equations


KE = 1/2mv^2
PE = mgh

The Attempt at a Solution


The first part I think I'm ok with. The tennis ball is dropped therefore no KE only PE.
PE = 9.8 x 20 = 196 Joules.

It is the second part that I don't really understand. What is it asking me? Can somebody maybe re-frase this part of the question. Thank you.
 
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  • #2
sorry. I forgot to turn that PE into KE by making 196 = 1/2v^2
This would give 19.79m/s
 
  • #3
RachelT said:

Homework Statement


Using the formulae for potential energy and kinetic energy, find the speed that a tennis ball hits the ground when dropped from a height of 20m.

With reference to the principle of conservation of energy, explain why you could use these equations and what assumptions you have made.

Homework Equations


KE = 1/2mv^2
PE = mgh

The Attempt at a Solution


The first part I think I'm ok with. The tennis ball is dropped therefore no KE only PE.
PE = 9.8 x 20 = 196 Joules.
You can't just drop mass from your equation because the ball's mass is not stated. :yuck:
Keep mass where it belongs, but represent it by the symbol m.
PE = m x 9.8 x 20 = 196m Joules
 
  • #4
Also best to avoid plugging in the number until the end.


PE = mgh
KE = 0.5mv2

0.5mv2 = mgh

Mass cancels.

Rearrange to give

v = SQRT(2gh)

Then put the numbers in.

As for part 2...

You need to explain why the KE the ball has when it hits the ground will be equal to the PE it had when dropped. What assumptions does that statement rely on?

Hint: Why would it be more reasonable to make that ssumption on the moon than on earth?

Make sure your answer mentions conservation of energy.
 
  • #5



I can explain the concept of conservation of energy in relation to the problem at hand. The principle of conservation of energy states that energy cannot be created or destroyed, it can only be transferred or converted from one form to another. This means that the total energy of a system remains constant. In this case, the system is the tennis ball and the Earth.

When the tennis ball is dropped from a height of 20m, it has a certain amount of potential energy due to its position above the ground. As it falls, this potential energy is converted into kinetic energy, which is the energy an object possesses due to its motion. This is represented by the equations for potential energy and kinetic energy, where PE = mgh and KE = 1/2mv^2.

By using these equations, we are assuming that there are no other external forces acting on the ball, such as air resistance or friction. This is because the principle of conservation of energy only applies in a closed system where there are no external forces. In reality, there will always be some loss of energy due to these external forces, but for the purposes of this calculation, we can assume that they are negligible.

Therefore, by using the equations for potential and kinetic energy, we can calculate the speed of the tennis ball when it hits the ground. This is because the total energy of the system (PE + KE) remains constant, and we can equate the initial potential energy (PE) to the final kinetic energy (KE) at the moment of impact. This is a direct application of the principle of conservation of energy.
 

What is the purpose of calculating the speed of a dropped tennis ball?

The purpose of calculating the speed of a dropped tennis ball is to better understand the concept of conservation of energy. By measuring the ball's speed, we can determine how much potential energy is converted into kinetic energy as the ball falls. This can help us understand the principles of energy transfer and conservation.

How do you calculate the speed of a dropped tennis ball?

The speed of a dropped tennis ball can be calculated using the equation v = √(2gh), where v is the speed, g is the acceleration due to gravity (9.8 m/s^2), and h is the height from which the ball was dropped. Simply plug in the values and solve for v to determine the speed of the ball.

Why is the conservation of energy important in this experiment?

The conservation of energy is important in this experiment because it allows us to understand how energy is transferred and transformed. In the case of a dropped tennis ball, potential energy is converted into kinetic energy as the ball falls. This principle applies to many real-world situations and helps us understand the underlying laws of physics.

What factors can affect the speed of a dropped tennis ball?

The speed of a dropped tennis ball can be affected by several factors, including the height from which it is dropped, air resistance, and the surface on which it is dropped. A higher drop height will result in a higher speed, while air resistance and a softer surface may slow the ball down. Additionally, the mass and size of the ball can also impact its speed.

How can the speed of a dropped tennis ball be used in practical applications?

The speed of a dropped tennis ball can be used in practical applications such as sports and engineering. In sports, understanding the speed of a ball can help athletes improve their skills and performance. In engineering, the principles of conservation of energy can be applied to design structures and machines that efficiently use and transfer energy.

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