- #1

leolaw

- 85

- 1

What will be the peak value of the current of a well-insulated [tex]0.03\mu F[/tex] capacitor connected to a 2.0-kV(rms) 720-Hz line?

So first I find the reactance of the capacitor, which is:

[tex]X_c=\frac{1}{2\pi fC}[/tex]

[tex]7.4k \Omega[/tex]

and then [tex]V_{rms} = I_rms * X_c[/tex]

[tex] 2*10^3 = I_{rms} (7.4 * 10^3)[/tex]

[tex] I_{rms} = 2.7 * 10^{-1} A[/tex]

so is this the right answer, or do i have to multiply it by [tex]\sqrt{2}[/tex] to get the peak value?