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Pellet on top of cylinder

  1. Feb 18, 2004 #1
    I need a little help with this problem.

    There is a small 0.2kg pellet sitting on the top of a cylinder of radius 0.8m.

    What is the value of the angle at which the pellet loses contact with the surface of the cylinder?

    I just need a little help on how to get started with this one. I was thinking about finding the point where the normal and tangential acceleration of the pellet were equal, but wasn't sure if this was the right path.

    Any other additional help would be greatly accepted.
     
  2. jcsd
  3. Feb 18, 2004 #2

    Doc Al

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    Staff: Mentor

    First, realize that the pellet is centripetally accelerated when it follows the cylinder. Then consider that the pellet leaves the cylinder when the normal force equals zero.
     
  4. Feb 18, 2004 #3
    I know the value of the normal acceleration is V^2/R, but how is this used to find the angle?
     
  5. Feb 18, 2004 #4
    Also, I know how to find the velocity of the pellet at a given angle. Does this lead to the answer?
     
  6. Feb 19, 2004 #5

    NateTG

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    Science Advisor
    Homework Helper

    You know what the forces are:
    The normal force and gravity. If you draw an FBD, you can determine the magnitude of the maximal centipetal acceleration due to gravity as a function of the angle of the pellet on the cylinder, and thus the height.

    Clearly the pellet leaves when the two are equal.
     
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