- #1

- 12

- 0

[tex]x^2 - 18 y^2 = 12[/tex]

Any suggestion?

I thought , we have to find [itex]\sqrt 18[/itex]and then find [tex]x/y[/tex]

BUT I was confused and then stopped solving

- Thread starter wii
- Start date

- #1

- 12

- 0

[tex]x^2 - 18 y^2 = 12[/tex]

Any suggestion?

I thought , we have to find [itex]\sqrt 18[/itex]and then find [tex]x/y[/tex]

BUT I was confused and then stopped solving

- #2

- 2,967

- 5

This equation has 2 unknowns. If you don't specify what set *x* and *y* are elements of, for example integer, it has an infinite set of solutions that can be represented parametrically as:

[tex]

\begin{array}{l}

x = \pm 2 \sqrt{3} \, \cosh{t} \\

y = \frac{2 \sqrt{3}}{3} \, \sinh{t}

\end{array}

[/tex]

[tex]

\begin{array}{l}

x = \pm 2 \sqrt{3} \, \cosh{t} \\

y = \frac{2 \sqrt{3}}{3} \, \sinh{t}

\end{array}

[/tex]

Last edited:

- #3

- 12

- 0

Sorry,

Both x & y are integers.

Both x & y are integers.

- #4

- 273

- 0

You might get more help if you posted this in the Number Theory section...

- #5

- 2,967

- 5

There is no solution.

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