1. The problem statement, all variables and given/known data A mass of 200 g is attached to the end of a cord 1.20 m long. The cord is hung from a horizontal beam and the mass is free to swing making a pendulum. The mass is released from rest at an angle of 60° from vertical. What will be the velocity of the mass at an angle of 30°, and at an angle of 0°? 2. Relevant equations F_c = m(v²/r) 3. The attempt at a solution I figured that since it seems to be traveling in a half circle type of movement...I could use the fact that the length of the string would be the radius...so 1.20m after that I did ƩF_y = ma_y mgcosθ = m(v²/r) the m's cancel so gcosθ = v²/r v = √(rgcosθ) And I figured that I could use that same equation to solve for each of the angles...i.e = √((1.20(9.8cos60)) = √((1.20(9.8cos30)) = √((1.20(9.8cos0)) Would this be correct? Or am I totally off here?