- #1
okalakacheekee
Alright, for the second order differential d^2 theta/dt^2 = -g/l sin theta, where l is length of pendulum, g is gravity, etc...how do you solve that exactly for theta as a function of time?
I substituted (w=omega) dw/dt for d2theta/dt2...and eventually got 1/2 w^2 = g/l cos theta + C...but that doesn't give me theta as a function of time?
Any help is appreciated...thanks
I substituted (w=omega) dw/dt for d2theta/dt2...and eventually got 1/2 w^2 = g/l cos theta + C...but that doesn't give me theta as a function of time?
Any help is appreciated...thanks