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Pendulum dilemma

  1. Nov 2, 2011 #1
    1. The problem statement, all variables and given/known data

    I am suppose to find a linear graph for the equation T=2pie(√L/√g)

    2. Relevant equations



    3. The attempt at a solution

    The best linear graph I could think of was L/T^2.

    Am I doing it right? Thanks.
     
  2. jcsd
  3. Nov 2, 2011 #2
    Yes.

    T[itex]^{2}[/itex] on y-axis and L on x-axis.
     
  4. Nov 2, 2011 #3
    Thank you very much. This has been like a huge thorn in my finger all day!
     
  5. Nov 2, 2011 #4
    I thought the slope was always y/x, so why isn't the slope of the graph T^2/L?
     
  6. Nov 2, 2011 #5
    Slope is NOT y/x but slope = [itex]\Delta[/itex]y/([itex]\Delta[/itex]x)
    or more exactly slope = dy/(dx).
     
  7. Nov 2, 2011 #6
    T = 2∏√(L/g)

    therefore T[itex]^{2}[/itex] = 4π[itex]^{2}[/itex]L/g

    so d(T[itex]^{2}[/itex])/dL = 4π[itex]^{2}[/itex]/g = slope
     
  8. Nov 2, 2011 #7
    oh that makes much more sense. thank you.
     
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