# Pendulum dilemma

## Homework Statement

I am suppose to find a linear graph for the equation T=2pie(√L/√g)

## The Attempt at a Solution

The best linear graph I could think of was L/T^2.

Am I doing it right? Thanks.

Yes.

T$^{2}$ on y-axis and L on x-axis.

Yes.

T$^{2}$ on y-axis and L on x-axis.

Thank you very much. This has been like a huge thorn in my finger all day!

I thought the slope was always y/x, so why isn't the slope of the graph T^2/L?

Slope is NOT y/x but slope = $\Delta$y/($\Delta$x)
or more exactly slope = dy/(dx).

T = 2∏√(L/g)

therefore T$^{2}$ = 4π$^{2}$L/g

so d(T$^{2}$)/dL = 4π$^{2}$/g = slope

T = 2∏√(L/g)

therefore T$^{2}$ = 4π$^{2}$L/g

so d(T$^{2}$)/dL = 4π$^{2}$/g = slope

oh that makes much more sense. thank you.