- #1

- 159

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## Homework Statement

I am suppose to find a linear graph for the equation T=2pie(√L/√g)

## Homework Equations

## The Attempt at a Solution

The best linear graph I could think of was L/T^2.

Am I doing it right? Thanks.

- Thread starter Crusaderking1
- Start date

- #1

- 159

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I am suppose to find a linear graph for the equation T=2pie(√L/√g)

The best linear graph I could think of was L/T^2.

Am I doing it right? Thanks.

- #2

- 993

- 13

Yes.

T[itex]^{2}[/itex] on y-axis and L on x-axis.

T[itex]^{2}[/itex] on y-axis and L on x-axis.

- #3

- 159

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Thank you very much. This has been like a huge thorn in my finger all day!Yes.

T[itex]^{2}[/itex] on y-axis and L on x-axis.

- #4

- 159

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I thought the slope was always y/x, so why isn't the slope of the graph T^2/L?

- #5

- 993

- 13

or more exactly slope = dy/(dx).

- #6

- 993

- 13

therefore T[itex]^{2}[/itex] = 4π[itex]^{2}[/itex]L/g

so d(T[itex]^{2}[/itex])/dL = 4π[itex]^{2}[/itex]/g = slope

- #7

- 159

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oh that makes much more sense. thank you.

therefore T[itex]^{2}[/itex] = 4π[itex]^{2}[/itex]L/g

so d(T[itex]^{2}[/itex])/dL = 4π[itex]^{2}[/itex]/g = slope

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