Pendulum dilemma

  • #1

Homework Statement



I am suppose to find a linear graph for the equation T=2pie(√L/√g)

Homework Equations





The Attempt at a Solution



The best linear graph I could think of was L/T^2.

Am I doing it right? Thanks.
 

Answers and Replies

  • #2
993
13
Yes.

T[itex]^{2}[/itex] on y-axis and L on x-axis.
 
  • #3
Yes.

T[itex]^{2}[/itex] on y-axis and L on x-axis.
Thank you very much. This has been like a huge thorn in my finger all day!
 
  • #4
I thought the slope was always y/x, so why isn't the slope of the graph T^2/L?
 
  • #5
993
13
Slope is NOT y/x but slope = [itex]\Delta[/itex]y/([itex]\Delta[/itex]x)
or more exactly slope = dy/(dx).
 
  • #6
993
13
T = 2∏√(L/g)

therefore T[itex]^{2}[/itex] = 4π[itex]^{2}[/itex]L/g

so d(T[itex]^{2}[/itex])/dL = 4π[itex]^{2}[/itex]/g = slope
 
  • #7
T = 2∏√(L/g)

therefore T[itex]^{2}[/itex] = 4π[itex]^{2}[/itex]L/g

so d(T[itex]^{2}[/itex])/dL = 4π[itex]^{2}[/itex]/g = slope
oh that makes much more sense. thank you.
 

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