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Pendulum Frequency

  1. Mar 19, 2007 #1
    1. The problem statement, all variables and given/known data

    A simple pendulum oscillates with frequency 2.30 Hz.
    (a) What is its frequency if it accelerates at 0.500 g upward?
    (b) What is its frequency if it accelerates at 0.500 g downward?

    2. Relevant equations

    f=1/[2(pi)(L/g)^.5]


    3. The attempt at a solution

    Won't frequency be constant? So both a and b are 2.30Hz?
     
  2. jcsd
  3. Mar 19, 2007 #2

    G01

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    If the pendulum is accelerating upward or downward the net acceleration the pendulum is experiencing will change. So, in this case, where g normally is in the formula, you must replace with the new net acceleration, call it a. So, what would the net acceleration be for each case. If you can find these values, then you can find the frequencies.
     
  4. Mar 19, 2007 #3
    So how about finding L? Before I just use f=2.3Hz and g=9.81 and solved for L. Is that correct?
     
  5. Mar 19, 2007 #4

    G01

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    Yes, The value of L found for when the pendulum is not accelerating will be the same in parts A and B. Nothing suggests the length of the string changes.
     
  6. Mar 19, 2007 #5
    So for part a g=9.81-0.5*9.81
    and b would be g=9.81+0.5*9.81?

    Thanks
     
  7. Mar 19, 2007 #6

    G01

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    That looks correct.
     
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