This is one question that's giving me a bit of trouble to handle. The Period of a pendulum is given by the following equation: where T= period of pendulum (seconds) L= Length of pendulum (meters) g= acceleration doe to gravity (meters per second2) Solve this equation in terms of L, T and pi. That means that g sould be by itself on one side of the equal sign and a combination of L, T, and pi should be on the other side of the equal sign. T=2(pi)*square.root.of(L/g) My attempt at the problem was: (T)/(2*pi)= square.root.of(L/g)2 Then I squared the right side of the equation and did the same on the left in order to cancel out the square root on the right. ((T)/(2*pi))2=(L/g) Afterwords, I tried to factor out the L by multiplying its inverse on the right and got: ((T)/(2*pi))2(1/L)=(1/g) There I get stuck, because I'm not too sure if he wanted it set equal to 1/g. So if anyone can send some feedback, then it would be greatly appreciated!