(adsbygoogle = window.adsbygoogle || []).push({}); This is one question that's giving me a bit of trouble to handle.

The Period of a pendulum is given by the following equation:

where T= period of pendulum (seconds)

L= Length of pendulum (meters)

g= acceleration doe to gravity (meters per second^{2})

Solve this equation in terms of L, T and pi. That means that g sould be by itself on one side of the equal sign and a combination of L, T, and pi should be on the other side of the equal sign.

T=2(pi)*square.root.of(L/g)

My attempt at the problem was:

(T)/(2*pi)= square.root.of(L/g)^{2}

Then I squared the right side of the equation and did the same on the left in order to cancel out the square root on the right.

((T)/(2*pi))^{2}=(L/g)

Afterwords, I tried to factor out the L by multiplying its inverse on the right and got:

((T)/(2*pi))^{2}(1/L)=(1/g)

There I get stuck, because I'm not too sure if he wanted it set equal to 1/g. So if anyone can send some feedback, then it would be greatly appreciated!

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# Homework Help: Pendulum Lab

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