1. The problem statement, all variables and given/known data A pendulum has a period of 4.50s on Earth. What is its period on Mars, where the acceleration of gravity is about 0.37 that on Earth? (2 sig figs) 2. Relevant equations T= 2Pi(L/g)^.5 3. The attempt at a solution first must solve for the length on earth L = g(T/2Pi)^2 = (9.8m/s^2)(4.5s/2Pi)^2 =489.7m now that i know the length i can take the same pendulum to mars and solve for T on mars T= 2Pi(L/.37g)^.5 = 2Pi(489.7m/(.37*9.8m/s^2))^.5 = 73 s mastering physics says I am wrong. What did I miss?