The problem is as follows:(adsbygoogle = window.adsbygoogle || []).push({});

Suppose the length of the pendulum is decreased by slowly pulling the string up through the

hole. The rate of decrease of length is to be extremely slow compared with the frequency of

oscillation, so that we can define a period of oscillation for each length of string. Find the change in energy of the pendulum as the length is shortened, from the work done in

pulling against the tension in the string. Show as a result that the action variable

J = E/ν is constant throughout the process.

H = E = J/(2*PI) * (g/L)^1/2

From what I understand

dE = J/(2*PI) * (g/(dL/dt))^1/2

and dv = 1/(2*PI) * (g/(dL/dt))^1/2

Hence dE= J dv

J =dE/dv

= E/v

I'm not sure if this is correct. The question can't be this simple and I think I'm missing soming from the question.

Also

For a pendulum, if the amplitude of oscillation is small, show that the energy of the pendulum is given by E = Jν .

I'm not sure how to get the right answer

0=theta 0' = theta dot

T = m/2 * L^2 *0' ^2

V = -mgL cos 0

p = 0mL^2

H = p^2/2mL^2 -mgL cos 0 =E

moving this around

p = (2mL^2 (E +mgL cos 0)) ^1/2

subing cos 0 = 1 - (0 ^2) /2

then intergrating p

I get

J = 2*Pi * (m^2 *L^3 *g)^1/2 * (E/mgL +1/2)

the answer would be correct if the +1/2 wasn't in the last term and I'm not sure where I hav maded a mistake in the intergration.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Pendulum problem

Can you offer guidance or do you also need help?

Draft saved
Draft deleted

**Physics Forums | Science Articles, Homework Help, Discussion**