# Pendulum swing/angle question

1. Sep 29, 2008

### meeklobraca

1. The problem statement, all variables and given/known data

You have a 0.35m long pendulum attached to the roof inside your car. Your car is travelling as a speed of 1m/s when it hits a concrete wall and stops immeadiately. If the pendulum is free to swing, to what maximum angle to the verticle does the pendulum swing upon impact.

2. Relevant equations

I dont have the slightet idea where to start. Im guessing we need to get some trig involved here because to find the angle we need at least the distance the pendulum swung.

I think we have a Vi that is 0 and a Vf that is 1 but again, im not sure how to use that to figure this out.

3. The attempt at a solution

2. Sep 29, 2008

I don't know where to begin with out a stopping distance. I would guess 90 degrees because it stops immeadiately, but that doesn't sound right.

3. Sep 29, 2008

### meeklobraca

Well does it help that this question is in a conservation of energy work sheet?

4. Sep 29, 2008

Do you have any other numbers (such as mass)?

5. Sep 29, 2008

### meeklobraca

Nah nothing else. LIke what ive been trying to rack my head around is trying to figure out the distance between where the pendulum starts, and where it reaches max angle. From there you can use some trig to get the angle, but I have no idea how to get that distance with the values we have.

6. Sep 29, 2008

I could do it with mass, but with out it I don't know where to start. Some one else might be able to help.

7. Sep 29, 2008

### meeklobraca

Im just saying this theoretically, but what if the mass was 5Kg. THen how would you solve it?

8. Sep 30, 2008

### meeklobraca

Its a fairly complicated process in this one, but as it was explained to me is that you have a starting point and then the stopping point of the pendulum as the car hits the wall. THe starting point has Ek and the stopping point is Ep. So you have to use 1/2mv2 = mgh and solve for h. Take the difference of h off the total length of the pendulum and create a right angle triangle and solve for the angle.

9. Sep 30, 2008

Yes but you would need mass for that, I thought you didn't have it.

10. Sep 30, 2008

### meeklobraca

mass can cancel each other out since theyre on each end of the equation

11. Sep 30, 2008

Yea I see now, I did this not long ago (clearly didn't rember it).
1/2v^2 = gh
h = 1/2v^2/g = 1/2*1/9.81 = 0.051
sin^-1(O/H)=sin^-1(0.051/0.35)= 8.38 degrees.
Is that what you got?

12. Sep 30, 2008

### meeklobraca

You have to take the .051 off the overall length of 0.35 to get the resting side, then you have 0.35 on the other side. so you .3/.35 inv cos and you get 31 degrees which is the answer

13. Sep 30, 2008