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Kaxa2000
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Does a pendulum swing demonstrate angular momentum, linear, both, or neither?
Kaxa2000 said:I believe its both because during the swing the bob has a linear momentum vector with the swing. This creates an angular momentum vector out of the plane of the pendulum swing. Once it reaches its max height during the swing the force of gravity causes it to fall back the other way creating a torque vector perpendicular to plane of swing.
I'm not sure if this is completely right...I ask for confirmation
Kaxa2000 said:No
Angular momentum : L = r x p
At top of swing when v = 0
p = 0
&
L = r
At bottom of swing
p = mv
L = r x p
So they are not conserved??
The conservation of pendulum swing refers to the principle that the total amount of energy in a swinging pendulum system remains constant. This means that as the pendulum moves back and forth, the energy is continuously converted between potential and kinetic energy, but the total amount remains the same.
The length of a pendulum does not affect its conservation of swing. This is because the conservation of energy in a pendulum system is dependent on the mass and velocity of the pendulum, not its length.
Yes, the weight of the pendulum does affect its conservation of swing. A heavier pendulum will have more kinetic energy and therefore will have a larger swing amplitude. However, the total amount of energy in the system will remain constant.
The conservation of pendulum swing can be impacted by factors such as air resistance, friction at the pivot point, and external forces such as pushing or pulling on the pendulum. These factors can cause the pendulum to lose some of its energy and affect its swing amplitude.
The concept of conservation of pendulum swing is important because it is a fundamental principle in physics that applies to many systems and helps to explain the behavior of objects in motion. It also allows us to predict the motion of a pendulum and understand its energy transformations.