(adsbygoogle = window.adsbygoogle || []).push({}); % Abundace Calc Error

here's the prob and my work can anyone help me figure out where i'm going wrong? thanks

The element silver has two naturally occurring isotopes with masses of 106.91 amu and 108.90 amu. What would be the percent abundance of the first isotope, if the atomic weight were 108.0429 amu?

108.0429 = 106.91*X + 108.90*Y (and since Y=1-X)

108.0429 = 106.91*X + 108.90 - 108.90*X

108.0429 - 108.90 = 106.91*X + 108.90*X

-(-1.99 = -0.8571*X) = 1.99 = 0.8571*X

X = 0.4307

Y= 0.5693

i did that and the online thing i enter the homework into says it's incorrect

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Percent Abundace Calc Error

**Physics Forums | Science Articles, Homework Help, Discussion**