Percent acetic acid by weight

Integral0

The molarity and percent by weight of the acetic acid in the vinegar. Use a value of 1.005 g/mL for the density of the vinegar.

Acetic acid molarity in vinegar = .208 mol / L

How do you calculate the Percent acetic acid by weight (using the acetic acid molarity)?

Thanks for the help.

Related Biology and Chemistry Homework Help News on Phys.org

Chemicalsuperfreak

Assume you've got one liter of solution, to simplify things. How many moles of acetic acid is that? How many grams of acetic acid is that? How many grams of solution do you have? Should be easy to figure out from there.

Integral0

RE

Well, I have .208 moles of solution and 13.3 g of Acetic acid . . . I have 78 grams of Vinegar so 13.3 / 78 = 17.0% ahh I see

thanks for the help

P.S. How do I become a chem super freak like you? sumitmanhas

hey how did u get 13.3 g of acetic acid from 0.208 moles provided that the molar mass is 60.5 . since, moles = mass/molar mass
therefore , mass = 60.5 * 0.208 = 12.58 grams ?
i have an assignment due on this , in the next 3 hrs. plz help someone ???

Borek

Mentor
Molar mass is 60.05, which makes 13.3 even more difficult to understand.

Check how to convert percentage to molarity - you can solve final formula for percentage.

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving