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Percent Change in Momentum

  1. Mar 11, 2007 #1
    % Change in Momentum

    1. I do not understand how to do this question as part of my revision. can anyone help? ''Calculate the % change in the momentum of the lorry from loaded to unloaded whilst travelling at a constant velocity of 13.41m/s''



    2. Momentum = mass x velocity? Loaded lorry weighs 3100kg unloaded weighs 2300kgs.
     
  2. jcsd
  3. Mar 11, 2007 #2
    would change be 25.8% decrease in momentum from loaded to unloaded?
     
  4. Mar 11, 2007 #3

    cristo

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    Yup, that looks correct to me.

    [In future, please show your work, as it is easier for someone to check your work than to do it themselves!]
     
    Last edited: Mar 11, 2007
  5. Mar 11, 2007 #4
    change = momentum_full - momentum unloaded = m1v - m2v = v(m1-m2)

    percentage change = (change / momentum_full) * 100%
     
    Last edited: Mar 11, 2007
  6. Mar 11, 2007 #5
    yeah, i know, i corrected it right after i'd posted it.
     
  7. Mar 11, 2007 #6

    cristo

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    Which is why I deleted my last post :smile:
     
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