Percent Change in Momentum

  • Thread starter spritchs
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  • #1
spritchs
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% Change in Momentum

1. I do not understand how to do this question as part of my revision. can anyone help? ''Calculate the % change in the momentum of the lorry from loaded to unloaded whilst travelling at a constant velocity of 13.41m/s''



2. Momentum = mass x velocity? Loaded lorry weighs 3100kg unloaded weighs 2300kgs.
 

Answers and Replies

  • #2
spritchs
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would change be 25.8% decrease in momentum from loaded to unloaded?
 
  • #3
cristo
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would change be 25.8% decrease in momentum from loaded to unloaded?

Yup, that looks correct to me.

[In future, please show your work, as it is easier for someone to check your work than to do it themselves!]
 
Last edited:
  • #4
dobry_den
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change = momentum_full - momentum unloaded = m1v - m2v = v(m1-m2)

percentage change = (change / momentum_full) * 100%
 
Last edited:
  • #5
dobry_den
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yeah, i know, i corrected it right after i'd posted it.
 
  • #6
cristo
Staff Emeritus
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yeah, i know, i corrected it right after i'd posted it.

Which is why I deleted my last post :smile:
 

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