1. The problem statement, all variables and given/known data Given the following equation: K2PtCl4 + 2 NH3 -----> Pt(NH3)2Cl2 + 2 KCl c) Starting with 34.5 g of NH3, and you isolate 76.4 g of Pt(NH3)2Cl2, what is the percent yield? 3. The attempt at a solution I had to balance the eqn, which was pretty easy. Then I determined what the limiting reagent is, given 34.5g NH3 (which was asked) and I deduced that NH3 was the LR and calculated the theoretical yeild of KCl to be 151g. Part C of the question is what I am having some difficulty with. Percentage yeild. I'm thinking that the plan for this problem is to calculate the moles of each and then just turn those numbers into percentages. But I don't think that's right. I kind of don't really know where to start otherwise. I could calculate the moles of each and then take a percentage by dividing moles of NH3 by the moles of Pt(NH3)2Cl2 and multiplying that by 100 to make a percentage figure. Need help on this one guys.