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Percentage problem

  1. Feb 6, 2005 #1
    a mixture of NaNO3 and Na2SO4 of mass 5.37g contains 1.61g of sodium, what is percentage by mass of NaNO3 in the mixture?
     
    Last edited: Feb 6, 2005
  2. jcsd
  3. Feb 6, 2005 #2
    Hmm. Sodium? Which formula is that?
     
  4. Feb 6, 2005 #3
    Um..........Na?
     
  5. Feb 6, 2005 #4

    chem_tr

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    You have already solved the question, just do the dividing operation and multiply by 100 to learn the percentage.
     
  6. Feb 6, 2005 #5
    Divide what by what? both compunds contain Na...
     
  7. Feb 6, 2005 #6

    chem_tr

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    1.61/5.37*100=29.98% total sodium is present in the mixture.

    Na=23, N=14, O=16, S=32 and NaNO3 is 48+14+23=85 g/mol, whereas Na2SO4 is 46+32+64=142 g/mol.

    Devise an equation, in which x moles of nitrate and y moles of sulfate is present, and make it equal to 5.37. Use mole amounts to learn x and y by making them equal to 1.61. It shouldn't be hard...
     
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