Percentage of NaNO3 in 5.37g Mixture: 1.61g Sodium

  • Thread starter physicsss
  • Start date
In summary, the mixture of NaNO3 and Na2SO4 of mass 5.37g contains 1.61g of sodium, making the percentage by mass of NaNO3 in the mixture 29.98%. This can be calculated by dividing 1.61g (the mass of sodium present) by 5.37g (the total mass of the mixture) and multiplying by 100. To determine the number of moles of NaNO3 and Na2SO4, an equation can be devised using their molecular weights and setting it equal to 5.37g. By setting the moles of NaNO3 and Na2SO4 equal to 1.61, the resulting equation can be solved
  • #1
physicsss
319
0
a mixture of NaNO3 and Na2SO4 of mass 5.37g contains 1.61g of sodium, what is percentage by mass of NaNO3 in the mixture?
 
Last edited:
Chemistry news on Phys.org
  • #2
Hmm. Sodium? Which formula is that?
 
  • #3
Um...Na?
 
  • #4
You have already solved the question, just do the dividing operation and multiply by 100 to learn the percentage.
 
  • #5
Divide what by what? both compunds contain Na...
 
  • #6
1.61/5.37*100=29.98% total sodium is present in the mixture.

Na=23, N=14, O=16, S=32 and NaNO3 is 48+14+23=85 g/mol, whereas Na2SO4 is 46+32+64=142 g/mol.

Devise an equation, in which x moles of nitrate and y moles of sulfate is present, and make it equal to 5.37. Use mole amounts to learn x and y by making them equal to 1.61. It shouldn't be hard...
 

1. What is the percentage of NaNO3 in the 5.37g mixture?

The percentage of NaNO3 in the 5.37g mixture is calculated by dividing the mass of NaNO3 (1.61g) by the total mass of the mixture (5.37g), then multiplying by 100. This gives a percentage of approximately 30% NaNO3 in the mixture.

2. How was the mass of NaNO3 determined in the mixture?

The mass of NaNO3 in the mixture was determined by measuring the total mass of the mixture (5.37g) and then subtracting the mass of the other components in the mixture. In this case, the mass of NaNO3 was determined by subtracting the mass of sodium (3.76g) from the total mass of the mixture.

3. What other methods can be used to determine the percentage of NaNO3 in the mixture?

Other methods for determining the percentage of NaNO3 in the mixture include using a chemical reaction to separate the components, using spectroscopy to measure the absorption of light by NaNO3, or using titration to determine the amount of NaNO3 in the mixture.

4. Why is it important to know the percentage of NaNO3 in the mixture?

Knowing the percentage of NaNO3 in the mixture is important for understanding the composition and properties of the mixture. It can also be used to calculate the amount of NaNO3 needed for a specific reaction or process.

5. Can the percentage of NaNO3 in the mixture change over time?

Yes, the percentage of NaNO3 in the mixture can change over time if the mixture is exposed to external factors such as heat, light, or other chemicals. These factors can cause the components in the mixture to react or decompose, altering the percentage of NaNO3 present.

Similar threads

Solubility of Sodium nitrate and nitrite
    • Chemistry
Replies
3
Views
696
Chemical Composition / Ingredients to create a product similar to RMR 86
    • Chemistry
Replies
2
Views
1K
Electrolysis of Na2SO4 on Submerged Aluminum
    • Chemistry
Replies
2
Views
1K
Chemistry Chemical Equation Balance: NaNO3 + NaOH + Zn -> NH3 + Na2ZnO2 + H2O
    • Biology and Chemistry Homework Help
Replies
5
Views
1K
Regenerating ion exchange resin
    • Chemistry
Replies
2
Views
641
Reactive metal wires in a fuel oxidizer mixture
    • Chemistry
Replies
1
Views
622
Sodium carbonate vs sodium bicarbonate
    • Chemistry
Replies
14
Views
2K
Questions about making galinstan
    • Chemistry
Replies
8
Views
3K
Anyone very knowledgeable in making body soap?
    • Chemistry
Replies
5
Views
763
How Can NaOH and NaNO3 be Separated via Crystallization Using Ethanol?
    • Chemistry
Replies
1
Views
3K

Hot Threads

Recent Insights

Back
Top