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Percentage yield calculations

  1. Dec 5, 2009 #1
    We were preparing Alkene from Alcohol & were asked to calculate percentage yield.
    We used 13.5 ml Cyclohexanol with 13.5 ml water & 7ml Sulfuric acid.

    To calculate % yield,i need theoretical mass..
    So i was calculating no.of moles of cyclohexanol & cyclohexene (the product) to get the theoretical mass.

    No of moles of cylcohexanol = m/molar mass
    mass = 13.5 ml x 0.926 g/ml (density) = 12.987 g
    No.of moles of cyclohexanol = 12.987/100.16 = 0.136 moles

    No.of moles of cyclohexne = no.of moles of cyclohexanol = 0.136 moles (from stoichiometry)
    Theoretical mass of cyclohexene = n x M
    =0.136 x 82.14 = 11.17104 g
    Is this calculation correct?
     
    Last edited: Dec 5, 2009
  2. jcsd
  3. Dec 5, 2009 #2

    The calculation looks correct. And as you said, next step is to find the number of moles cyclohexene. 1 mole cyclohexanol yield 1 mole cyclohexane, so there are the same numbers of molecules, but you should think about if two molecules have the same molar mass =)
     
  4. Dec 5, 2009 #3
    I edited the first post with the continued calculations.Can u check that for me, please?
     
  5. Dec 5, 2009 #4
    It looks ok.
     
  6. Dec 5, 2009 #5
    Thanku very much :D
     
  7. Dec 5, 2009 #6
    No problem, you know how to calculate the %yield?
     
  8. Dec 5, 2009 #7
    Yes :) Actual mass / Theoretical x 100
    :D
    Thanks for asking,really :) Most helplers here just make me feel inferior lol.
     
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