- #1

mess1n

- 24

- 0

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W = q [tex]\int \textbf{E} . \textbf{dr}[/tex] [ the work done in moving a charge q (sorry about the formatting, it's meant to all be one line)]

... can be written as the

d(-1/r) = [tex]\frac{\textbf{r} . \textbf{dr}}{r^{3}}[/tex]

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W = q [tex]\int \textbf{E} . \textbf{dr}[/tex] [ the work done in moving a charge q (sorry about the formatting, it's meant to all be one line)]

... can be written as the

*'perfect differential'*d(-1/r) when**E**is given by Coulomb's Law:d(-1/r) = [tex]\frac{\textbf{r} . \textbf{dr}}{r^{3}}[/tex]

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Cheers guys,

Andrew