"Perfect" square? Is a perfect square only "perfect" if the root is a whole number? Or does the term just dictate that decimals must eventually terminate? For instance: [tex]\displaystyle{\sqrt{59.29} = 7.7}[/tex]
http://en.wikipedia.org/wiki/Perfect_square Thus a perfect square always has a square root that has no decimal expansion.
A number always has a "decimal expansion". Integers just happen to have all 0s after the decimal point! A "perfect square" is the square of an integer. 52.29 is NOT a perfect square.
Though 5229 is a perfect square. If you have a rational number as the result of a root, then the thing inside the root is the square of a rational (in this case, (77/10)^2 = 5229/100), so there are two perfect squares involved somewhere. Other than these musings, all the replies above are, of course, right.
Ooops! The original post does say "59.29", not "52.29" so you were right and I was wrong. I hate when that happens!