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Period of a pendulum is measured to be 3.00 s

  1. Oct 29, 2011 #1
    1. The problem statement, all variables and given/known data

    The period of a pendulum is measured to be 3.00 s in the reference frame of the pendulum.



    2. Relevant equations
    What is the period when
    measured by an observer moving at a speed of 0.960c relative to the pendulum?


    3. The attempt at a solution

    I dont want to change the referencial frames. So:

    Δt = 3.00 s


    Δt = [itex]\frac{Δto}{\sqrt{1-0.9216}}[/itex]
    Δto = 0.84s

    So, the period of pendulum measured by the observer (with speed 0.960c) is 0.84 s ?

    right?

    The solution, they changed the frames. So pendulum moves with 0.960c.

    Δto = 3,00s and Δt= 10.00s.

    Is my solution correct, or i need to change the frames?
     
  2. jcsd
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