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Period of the resulting SHM?

  1. Nov 28, 2007 #1
    The 3.00 kg cube has edge lengths d = 6.30 cm and is mounted on an axle through its center. A spring (k = 950 N/m) connects the cube's upper corner to a rigid wall. Initially the spring is at its rest length. If the cube is rotated 3.00° and released, what is the period of the resulting SHM?

    Please provide a solution rather than just an answer. I really appreciate any help:)
     
  2. jcsd
  3. Nov 28, 2007 #2

    Dick

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    You are going to find that you won't get much of a response by just throwing questions into a template and posting them. You need to show that you've made at least some attempt at solving the problem on your own.
     
  4. Nov 29, 2007 #3
    what if i dont get it at all :(
     
  5. Nov 29, 2007 #4

    Dick

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    Then you should probably start with a simpler question where you are only partially lost. For this problem convert the rotational motion of the cube into a distance the spring is stretched (a picture would really help here - I'm not sure what the geometry is). Then determine an approximate linear relation between the angle of rotation and the torque on the cube which, together with knowing the moment of inertial of the cube, gives you a SHO for small angular displacements.
     
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