Okay. If hot Potassium PERMANGANATE (KMnO4-) with concentrated acid, is added to Ethene, what will form. If I look at my textbook, I can deduce that first the alkene would oxidise into a di-diol. Then the bond splits, then; a hydrogen would get replaced by an oxygen otherwise, the OH would get replaced by an oxygen. If I follow this pattern for Ethene, I think 2 Methanoic Acids should be formed, instead 2 Carbon Dioxides are formed according to my textbook! So what are the products? Also can someone give me a link or some information about the mechanism involved here.