(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A spherical capacitor (shell radiuses a and b, a<b) has the space between the shells filled with a dielectric, and the permittivity changes as a function of the radius so that the energy density stays constant (when radius R=a, then e_{r}=e_{1}). Find the permittivity as a function of R.

2. Relevant equations

[tex]E=\frac{Q}{4 \pi \epsilon R^2}[/tex]

[tex]\epsilon = \epsilon _0 \epsilon _r[/tex]

Energy density:

[tex]u=\frac{1}{2} \epsilon E^2=

\frac{1}{2} \epsilon _0 \epsilon _r \frac{Q^2}{16 \pi ^2 \epsilon _0^2 \epsilon _r^2 R^4}[/tex]

3. The attempt at a solution

I don't have a clue how this should be done. Now, u reduces to:

[tex]u=\frac{1}{2} \epsilon E^2=

\frac{1}{2} \epsilon _0 \epsilon _r \frac{Q^2}{16 \pi ^2 \epsilon _0^2 \epsilon _r^2 R^4} = \frac{Q^2}{32 \pi ^2 \epsilon _0 \epsilon _r R^4}[/tex]

So I guess that leaves me with only e_{r}to play with, in order to get rid of the R^4, which in turn is required to be taken out if u is needed to be constant. But as it was initally required that when R=a then e_{r}=e_{1}, and I don't know how I could get rid of the R.

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# Homework Help: Permittivity of a capacitor

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