(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

In How many ways can six men and two boys be arranged in a row if:

a. The two boys are together?

b. The two boys are not together?

c. There are at least three men separating the boys?

2. Relevant equations

P= N!

(n-r)!

Identical n objects.

N!

n1 x n2 x...x nk

3. The attempt at a solution

A.Answer: 2(7!) = 10,080

B.Answer: 8!-2(7!) = 30,240

For C i have so far, divided the total into 4 groups each boy is a seperate one and 2 groups of 3 men... I set the boys as identical objects so they arent set in alternating pairs ( AB, BA would just be one) so i divide that by 2... and the 2 groups of 3 men can alternate withing each other so thats 3!^2

4! *3!*3!

2!

Im sure this is not the right way to go, and i think i have to find the total number the boys are seperated for atleast 3, 4,5,6 men and add them all.

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Permutation Problem

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