Perpendicular vector

  • Thread starter EvLer
  • Start date
  • #1
458
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Homework Statement


how do I find the basis for all vectors that are perpendicular to both
v1 = (1,1,0,0) and
v2 = (1,0,1,1)

If it were 3-D I could find a normal vector via cross product, but in n-dimensions.... what do I do?

My one thought is to arrange and solve linear homogeneous system:
[v1][x] = 0
[v2][y] = 0

since RHS is the dot product of the row vector (v1 or v2) and the column [x,y]t, and for vectors to be perpendicular, their dot product should be 0.
Is that correct?

Thanks in advance.
 

Answers and Replies

  • #2
quasar987
Science Advisor
Homework Helper
Gold Member
4,783
18
If I understood correctly and you intend to solve the matrix equation

[tex]\left(
\begin{array}{cccc}
1 & 1 & 0 & 0\\
1 & 0 & 1 & 1
\end{array}
\right)\left(
\begin{array}{c}
x_1&x_2&x_3&x_4
\end{array}\right)=
\left(\begin{array}{c}
0&0
\end{array}
\right)[/tex]

then this is what I would do also.
 

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