dy/dx = (y-1)^2 given the initial condition y(0) =1 find an explicit solution.(adsbygoogle = window.adsbygoogle || []).push({});

separation of variables gives:

(y-1)^-2 dy = dx

integrating both sides I get

-(y-1)^-1 = x + c

-1= (y-1)(x+c)

-1/(x+c) = y - 1

y= 1 - 1/(x+c) but how can the intial condition work?

no value of c will make 1= 1 - 1(0+c)

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# Perplexed by this simple problem Please help

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