The higher order psi are written with larger epsilon factors in front but the higher order psi are precisely the ones that are meant to more exactly approach the purturbed system however we are decreasing its importance. Is the reason because they can also more easily deviate greater from the true solution?(adsbygoogle = window.adsbygoogle || []).push({});

It seems that in any purturbed system we are increasing the energy? Or can we decrease it as well? But if we decrease it we will still be adding the higher order energies which may be less then the unperturbed system but adding positive terms will always mean increasing in energy.

http://en.wikipedia.org/wiki/Perturbation_theory_(quantum_mechanics)

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# Perturbation question

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