The higher order psi are written with larger epsilon factors in front but the higher order psi are precisely the ones that are meant to more exactly approach the purturbed system however we are decreasing its importance. Is the reason because they can also more easily deviate greater from the true solution?(adsbygoogle = window.adsbygoogle || []).push({});

It seems that in any purturbed system we are increasing the energy? Or can we decrease it as well? But if we decrease it we will still be adding the higher order energies which may be less then the unperturbed system but adding positive terms will always mean increasing in energy.

http://en.wikipedia.org/wiki/Perturbation_theory_(quantum_mechanics)

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Perturbation question

Loading...

Similar Threads - Perturbation question | Date |
---|---|

Question regarding time independent perturbation theory | Feb 4, 2015 |

Error in perturbation series question | Jul 6, 2013 |

Question about Quantum + Thermodynamic Perturbation theory | Apr 27, 2012 |

Question on time-independent perturbation theory | Dec 5, 2011 |

Question on perturbation theory | Oct 19, 2011 |

**Physics Forums - The Fusion of Science and Community**