# Peskin Page 284

Hi,

I am studying Peskin's An Introduction To Quantum Field Theory. On the beginning of page 284, the authors say We can turn the field $\phi_S(x_1)|\phi_1\rangle=\phi_1(x_1)|\phi_1\rangle$. I tried hard to prove this relation but still can't get it right. Could anyone give me some hints? Thanks.

Last edited:

vanhees71
Gold Member
2019 Award
It's a bit strangely formulated. The generalized kets $|\varphi \rangle$ are defined as generalized eigenstates of the field operators (here in the Schrödinger picture of time evolution), i.e.,
$$\hat{\phi}_S(\vec{x}_1) |\varphi \rangle = \varphi(x) |\varphi \rangle.$$
Note that $\hat{\phi}_S$ is a field operator in the Schrödinger picture while $\varphi$ is a (complex or real-valued, depending on whether you describe charged or strictly neutral scalar bosons) c-number field.

Last edited:
Bill_K
Note that $$\hat{\phi}_S[/itex] is a field operator in the Schrödinger picture while $\varphi$ is a (complex or real-valued, depending on whether you describe charged or strictly neutral scalar bosons) c-number field. This is difficult to read. Please format your LaTeX correctly, or use UTF. vanhees71 Science Advisor Gold Member 2019 Award This is difficult to read. Please format your LaTeX correctly, or use UTF. Done (butt no UTF, which is hard to read either ;-)). It's a bit strangely formulated. The generalized kets $|\varphi \rangle$ are defined as generalized eigenstates of the field operators (here in the Schrödinger picture of time evolution), i.e., [tex]\hat{\phi}_S(\vec{x}_1) |\varphi \rangle = \varphi(x) |\varphi \rangle.$$
Note that $\hat{\phi}_S$ is a field operator in the Schrödinger picture while $\varphi$ is a (complex or real-valued, depending on whether you describe charged or strictly neutral scalar bosons) c-number field.

Thanks! That makes sense but I still don't understand why this given state is an eigenstate of field operators with eigenvalue being the field amplitudes at some specific position.

Thanks! That makes sense but I still don't understand why this given state is an eigenstate of field operators with eigenvalue being the field amplitudes at some specific position.

Because that's how we're defining the state $|\phi_1\rangle$. We're trying to pick out the state in the Hilbert space that, when you hit it with the field operator at any position $x$, will give you an eigenvalue equal to the c-number $\phi(x)$. It's a way of going from states in a Hilbert space to simple c-number functions, so that you can perform the functional integral over them.

Last edited: