I have calculated the PH-value for this following solution:(adsbygoogle = window.adsbygoogle || []).push({});

100 mL 0,102 M HCL and 100 mL 0,0780 M NaOH.

To calculate the pH in the this solution first I must calculate the number of moles [itex]n_{[H_3O^+]}[/itex].

[itex]n_{[H_3 O^{+}]} = 0,100 L \cdot 0,0102 \ mol/L + 0,100 L \cdot 0,0780 mol/L = 0,018 mol[/itex]

This means that [itex][H_3 O^{+}] = \frac{0,018 mol}{0,200 L} = 0,09 mol/L[/itex]

pH for the solution is then [itex]pH = \textrm{-log}(0,09) = 1,05[/itex]

I would appriciate if somebody would look at my calculation and then tell me if its accurate ??

Many thanks in advance.

Sincerely

Fred

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# PH-calculation question.

Loading...

**Physics Forums | Science Articles, Homework Help, Discussion**