PH calculation

  • #1
I have a short question concerning the dilution of a 0.01M solution of HCN. I need to dilute 40cm3 of the above to give a solution with a pH of 6. Given the Ka of HCN is 4.8*10^-10 I obtain the concentration of HCN necessary in the new volume:2.08*10^-3M. Therefore the volume has to be multiplied by 0.01/2.08*10^-3 to give a new volume of 192cm3. Is it therefore that the volume of water necessary to add is 192-40=152cm3? Thx, Joe
 

Answers and Replies

  • #2
Borek
Mentor
28,816
3,318
Yes, you are correct. I have checked it using BATE :wink:
 

Related Threads on PH calculation

  • Last Post
Replies
7
Views
11K
  • Last Post
Replies
4
Views
4K
  • Last Post
Replies
6
Views
3K
  • Last Post
Replies
6
Views
2K
N
  • Last Post
Replies
8
Views
40K
  • Last Post
Replies
2
Views
7K
  • Last Post
Replies
18
Views
2K
  • Last Post
Replies
3
Views
686
Replies
15
Views
4K
Replies
20
Views
163K
Top