Calculate the pH of the solution
a) 23.0 ml of 6.29 M HCl is added to 160.0 ml of distilled water
pH = -log [H]
Kw = 1 x 10^-14
The Attempt at a Solution
For part a) I found the no.of moles Of HCl as 0.14467mol and from this I found the no.of moles of Hydrogen ions as 0.14467 mol
then I found the concentration of Hydrogen ions as 0.9041875
then pH as 0.04374
but the answer is coming worng .... and I also don't know the correct answer because this is an online hw.
Please someone tell where I'm wrong .... any kind of guide or help.