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**[SOLVED] pH of solution**

## Homework Statement

What is the pH of a solution in which 30.0mL of 0.010 M NaOH are added to 10.0mL of .010 M H2SO4?

## Homework Equations

## The Attempt at a Solution

So first thing I did was write the equation.

2NaOH + H2SO4 ----> Na2SO4 + 2H2O

I never used this equation after this which makes me think I already messed up. I perform the following:

.03L(.010M) = 3*10^-4 mol NaOH

.01L(.010M) = 1*10^-4 mol H2SO4

I then compute concentration of H2SO4 by: 1*10^-4/.01L = .01

pH = -log(.01) = 2.0 pH

I suspect I am missing something here. Any pointers?

Thanks