PH solution

  • Thread starter chawki
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  • #26
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n=C*V = 2*10-4*350= 0.07mol
 
  • #27
Borek
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OK, now how many moles of NaOH will react with 0.07 moles of H+? Do you know what the reaction is? Reaction equation?
 
  • #28
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2 NaOH + H2SO4 ---> Na2SO4 + 2 H2O
 
  • #29
Borek
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This reaction is correct, but it is not what I am asking about.

I am not asking about the reaction with sulfuric acid, but about reaction with H+.
 
  • #30
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Ahhh i don't know that one :eek:
 
  • #31
Borek
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Can you write NaOH in dissociated form?
 
  • #32
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sure
NaOH ----> Na+ + OH-
 
  • #33
Borek
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OK, now, what would happen when you add H+ to the mix?

H+ + Na+ + OH- -> ???
 
  • #34
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i dont know...but why we will add H+
 
  • #35
Borek
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Why? Because the question is about reaction between H+ and OH-. You have a solution of H+ and you add solution of OH- (Na+ and SO42- don't take part in the reaction, they are so called spectators).

What simple, electrically neutral molecule can be a product of reaction between H+ and OH-? Try to guess, it is so simple you will hate yourself you have not realized it earlier.
 
  • #36
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sulphuric has 2 protons.

so ph =-log(0.0004)

=-(log4-4)
=-(0.6021-4)
=3.3979
 
  • #37
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1 hydrogen has 1 proton but in sulphuric there are 2 hydrogen
 
  • #38
Borek
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sulphuric has 2 protons.

so ph =-log(0.0004)

=-(log4-4)
=-(0.6021-4)
=3.3979

This is wrong, please reread the question.

And read forum rules, giving final answers is against them. Not to mention giving wrong final answers.
 
  • #39
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Hello Borek o:)
please check this:

CA*VA=CB*VB
2*10-4*350=mB/40
mB=2*10-4*350*40 = 2.8g

That's it ?
 
  • #40
Borek
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2.8g of NaOH it is.
 
  • #41
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2.8g of NaOH it is.

Yay :tongue2: thank you Borek o:)
 

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