Hi, I got a problem with something regarding to chemistry. How can you determine the pH of a solution with two Acids? The question says that A 50.00 mL aqueous solution is made by mixing the following two solutions: 10.00mL 1x10^-9M HCl 50.00mL 1*10^-4 M CH3COOH (Ka= 1.8*10^-5) a) What is the Cl^- in the 50.00mL solution? b)What is the pH in the 50mL solution? c) What is the [CH3COOH] in the 50mL solution? thanks!