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Phase angle of a string

A transverse, sinusoidal wave is traveling along a string. It moves in the negative x-direction, and it has an amplitude of 5 cm. At time t=0, the point at x=0 is at a displacement of 4 cm and is traveling upward. What is the phase angle in degrees?



2. Homework Equations
x = A*cos([tex]\omega[/tex]*t+[tex]\phi[/tex])


3. The Attempt at a Solution

At t=0, [tex]\omega[/tex]*t = 0, so x = A*cos([tex]\phi[/tex]). Therefore, [tex]\phi[/tex] = arccos(x/A) = arccos(.8) = 36.87.

The acceleration is negative and the velocity is positive, so the angle is 360 - 36.87 = 323.13 degrees, right?
 

Answers and Replies

335
0
The equation you just used is not trustworthy for waves.It can be only generalized to SHM.

You must use wave equations to be more sure in your answers.

y= A sin ( k*x-omega*t + phase angle)
 

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