A transverse, sinusoidal wave is traveling along a string. It moves in the negative x-direction, and it has an amplitude of 5 cm. At time t=0, the point at x=0 is at a displacement of 4 cm and is traveling upward. What is the phase angle in degrees?(adsbygoogle = window.adsbygoogle || []).push({});

2. Relevant equations

x = A*cos([tex]\omega[/tex]*t+[tex]\phi[/tex])

3. The attempt at a solution

At t=0, [tex]\omega[/tex]*t = 0, so x = A*cos([tex]\phi[/tex]). Therefore, [tex]\phi[/tex] = arccos(x/A) = arccos(.8) = 36.87.

The acceleration is negative and the velocity is positive, so the angle is 360 - 36.87 = 323.13 degrees, right?

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# Homework Help: Phase angle of a string

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