A large punch bowl holds 4.75 kg of lemonade (which is essentially water) at 20.0°C. A 2.00 kg ice cube at -10.2°C is placed in the lemonade. What is the final temperature of the system, and the amount of ice (if any) remaining? Ignore any heat exchange with the bowl or the surroundings.(adsbygoogle = window.adsbygoogle || []).push({});

can someone please tell me how to solve this problem?

so far i have:

(4.75kg)(4186J/kg°C)(20°C) = 397670J

(2kg)(2090J/kg°C)(10.2°C) = 426360J

(2kg)(335000J/kg) = 670000J

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# Homework Help: Phase Changes and Energy Conservation

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