1. The problem statement, all variables and given/known data Two sound fonts make plain armonic waves with the same amplitude and frequency. If f=200 Hz and V=340 m/s, the phase difference in a point situated 8m away from one font and 25 m away from the other one will be... 2. Relevant equations V=Yf Y: Wave longitude Phase Difference=kr2-kr1 (Found it online and is so far the only one I know about) 3. The attempt at a solution Y=V/f=340/200=17/100 TT=Pi K=2TT/Y K=2TT/(17/100) Phase Difference=k(r2-r1) P.D=(2TT/(17/100))*17 P.d=2TT*100 Nut in the answer sheet it says the answer is: The waves are in phase. Please explain why?