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Phase difference.

  • #1

Homework Statement



Light of free space wavelength 600 nm (6000 Å) travels 1.6 10
-6
m in a medium of
index of refraction 1.5.
Find:
1. the optical path length, [This is the physical path length x refractive index.]
2. the wavelength in the medium, and
3. the phase difference after moving that distance, with respect to light travelling the
same distance in free space.




Homework Equations





The Attempt at a Solution



just for part 3 I got the right answer but Im just a little confused if my resoning is right.

the phase difference I calculated using d∏/λ I used Pi since the refractive index was not an integer so I thought it would be destructive intefeerence.

The answer comes out to be 8∏/3 but I am a little confused on why?
 

Answers and Replies

  • #2
NascentOxygen
Staff Emeritus
Science Advisor
9,243
1,068
Can you calculate the path length through that medium? (express your answer in wavelengths)
 
  • #3
Can you calculate the path length through that medium? (express your answer in wavelengths)
path length= actual length × (refractive index)

→ pathlength/wavelength.

= λ wavelengths


??
 

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