Phase velocity question

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  • #1
asdf1
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why is phase velocity v=w/k ?
 

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  • #2
arildno
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Let us look at a typical harmonic wave, [tex]f(x,t)=a\sin(kx-\omega{t})[/tex]
Here, a,k,[tex]\omega[/tex] are constants, where a is the amplitude, k the wave number and [tex]\omega[/tex] the frequency.

Rewrite this in the following form:
[tex]f(x,t)=a\sin(k(x-\frac{\omega}{k}t))[/tex]
Do you see that if [tex]x-\frac{\omega}{k}t=s[/tex] where s is a CONSTANT, makes the value of f constant as well (equal to [tex]a\sin(ks)[/tex])?
But that means, that the signal value [tex]a\sin(ks)[/tex] can be regarded as MOVING ALONG THE POSITIVE X-DIRECTION WITH VELOCITY [tex]\frac{\omega}{k}[/tex]!
For, (remembering that s is constant) we have the trajectory for our signal:
[tex]x=s+\frac{\omega}{k}t[/tex]
and this simply shows what the propagation velocity of our signal is..
 
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  • #3
asdf1
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@@a
"But that means, that the signal value can be regarded as MOVING ALONG THE POSITIVE X-DIRECTION WITH VELOCITYw/k !"
can you explain that a little clearer?
 

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