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Phasor Analysis

  1. Nov 13, 2016 #1
    1. The problem statement, all variables and given/known data
    steady-state current through the loop will be of the form Bsin(1000t +b). What is the phase angle 'b'? in rads

    2. Relevant equations

    3. The attempt at a solution

    The answer is meant to be 0.46rads/s. However Im getting 9.65x10^-5??
    I have no idea what I did wrong.

    I first converted everything into the phasor domain. Then I used voltage division to get the voltage drop across the resistor. Then I used Ohms Law to get the current through the resistor which is the same as the current through the circuit.
  2. jcsd
  3. Nov 13, 2016 #2


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    Staff: Mentor

    Check your calculation for the impedance of the inductor. The formula for the impedance of an inductor is not he same as that of a capacitor.

    Don't be afraid to promote j's in the denominator to the numerator. If you have a value like ##1/0.25j##, then this can become ##-4j##.

    You don't need to do any voltage division here. Simply sum up the impedances to find the total impedance. Then apply Ohm's law directly: ##I = E/Z## (where E is the applied potential difference across Z).
  4. Nov 13, 2016 #3
    Finally got it. Thank you soo much.
    It says in my lecture notes that inductors can be described be V = jwLI or I = 1/jwL * V
    It says nothing else. How do I know like what to use when? I mean say im converting a 2H inductance into the phasor form, how do I know what to use?
  5. Nov 13, 2016 #4


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    Staff: Mentor

    ##Z_L = j \omega L##

    ##Z_C = \frac{1}{j \omega C}##
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