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## Homework Statement

(Note, my answer below is also wrong. I've attempted this problem for about 1 hour now and I can't figure it out.)

## Homework Equations

KCL (Kirchoffs Current Law)

Z for the capacitor, Z = 1/(jwC)[/B]

## The Attempt at a Solution

I'm using KCL at V1 with the following convention: +ve for current flowing out of the node, -ve for current flowing in

If the bottom of our circuit is the reference:

V2 = Vs

KCL at Node 1

-i1(t) + i2(t) + V1/23 - (Vs-V1/(-40j) = 0

Now I convert all the current and voltage functions to phasors.

i1(t) = 0.2(60d)

i2(t) = 0.1(-90d)

Vs(t) = 10(-180d)

Subbing in to above...

-0.2(60d) + 0.1(-90d) + V1/23 - (10(-180d))/(-40j) + V1/(-40j) = 0

V1( 1/23 + 1/(-40j) ) = 0.2(60d) - 0.1(-90d) + 10(-180d) / (-40j)

V1 = (0.1 + 0.1732j + 0.1j - 10/(40j)) / (1/23 + 1/(-40j))

V1 = 6.93 + 8.05j

Converting this to phasor form,

V=10.622(40.3d)

But this is also wrong. I can't figure out what I'm doing wrong.

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